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An example of a Quadratic Equation:

The function makes nice curves like this one:

## Name

The name Quadratic comes from “quad” meaning square, because the variable gets

squared

(like x2).

It is also called an “Equation of

Degree

2″ (because of the “2” on the x)

## Standard Form

The Standard Form of a Quadratic Equation looks like this:

• a, b and c are known values. a can’t be 0.
• x” is the

variable

or unknown (we don’t know it yet).

Here are some examples:

 2x2 + 5x + 3 = 0 In this one a=2, b=5 and c=3 x2 − 3x = 0 This one is a little more tricky: Where is a? Well a=1, as we don’t usually write “1x2“ b = −3 And where is c? Well c=0, so is not shown. 5x − 3 = 0 Oops! This one is not a quadratic equation: it is missing x2 (in other words a=0, which means it can’t be quadratic)

## Have a Play With It

Play with the “

” so you can see:

• the function’s graph, and
• the solutions (called “roots”).

As we saw before, the Standard Form of a Quadratic Equation is

ax2 + bx + c = 0

But sometimes a quadratic equation doesn’t look like that!

For example:

In disguise In Standard Form a, b and c
x2 = 3x − 1 Move all terms to left hand side x2 − 3x + 1 = 0 a=1, b=−3, c=1
2(w2 − 2w) = 5

Expand

(undo the

brackets

),
and move 5 to left

2w2 − 4w − 5 = 0 a=2, b=−4, c=−5
z(z−1) = 3 Expand, and move 3 to left z2 − z − 3 = 0 a=1, b=−1, c=−3

Xem thêm: Điểm sự kiện nổi bật từ 12 đến 18-12

## How To Solve Them?

The “solutions” to the Quadratic Equation are where it is equal to zero.

They are also called “roots“, or sometimes “zeros

There are usually 2 solutions (as shown in this graph).

And there are a few different ways to find the solutions:

We can

(find what to multiply to make the Quadratic Equation)

Or we can

Complete the Square

Or we can use the special Quadratic Formula:

Just plug in the values of a, b and c, and do the calculations.

We will look at this method in more detail now.

### Plus/Minus

First of all what is that plus/minus thing that looks like ± ?

The ± means there are TWO answers:

x = −b + √(b2 − 4ac) 2a

x = −b √(b2 − 4ac) 2a

Here is an example with two answers:

But it does not always work out like that!

• Imagine if the curve “just touches” the x-axis.
• Or imagine the curve is so high it doesn’t even cross the x-axis!

This is where the “Discriminant” helps us …

### Discriminant

Do you see b2 − 4ac in the formula above? It is called the Discriminant, because it can “discriminate” between the possible types of answer:

• when b2 − 4ac is positive, we get two

Real

solutions

• when it is zero we get just ONE real solution (both answers are the same)
• when it is negative we get a pair of

Complex

solutions

Complex solutions? Let’s talk about them after we see how to use the formula.

Just put the values of a, b and c into the Quadratic Formula, and do the calculations.

### Example: Solve 5x2 + 6x + 1 = 0

Coefficients are:a = 5, b = 6, c = 1
Quadratic Formula:x = −b ± √(b2 − 4ac) 2a
Put in a, b and c:x = −6 ± √(62 − 4×5×1) 2×5
Solve:x = −6 ± √(36− 20) 10
x = −6 ± √(16) 10
x = −6 ± 4 10
x = −0.2 or −1

Answer: x = −0.2 or x = −1

And we see them on this graph.

 Check -0.2: 5×(−0.2)2 + 6×(−0.2) + 1 = 5×(0.04) + 6×(−0.2) + 1 = 0.2 − 1.2 + 1 = 0 Check -1: 5×(−1)2 + 6×(−1) + 1 = 5×(1) + 6×(−1) + 1 = 5 − 6 + 1 = 0

### Remembering The Formula

A kind reader suggested singing it to “Pop Goes the Weasel”:

 ♫ “x is equal to minus b ♫ “All around the mulberry bush plus or minus the square root The monkey chased the weasel of b-squared minus four a c The monkey thought ’twas all in fun ALL over two a” Pop! goes the weasel”

Try singing it a few times and it will get stuck in your head!

Or you can remember this story:

x = −b ± √(b2 − 4ac) 2a

“A negative boy was thinking yes or no about going to a party,
at the party he talked to a square boy but not to the 4 awesome chicks.
It was all over at 2 am.

Xem thêm: Nitrat, nitrit trong nước

## Complex Solutions?

When the Discriminant (the value b2 − 4ac) is negative we get a pair of

Complex

solutions … what does that mean?

It means our answer will include

Imaginary Numbers

. Wow!

### Example: Solve 5x2 + 2x + 1 = 0

Coefficients are:a=5, b=2, c=1
Note that the Discriminant is negative:b2 − 4ac = 22 − 4×5×1
= −16
Use the Quadratic Formula:x = −2 ± √(−16) 10

√(−16) = 4i
(where i is the imaginary number √−1)

So:x = −2 ± 4i 10

Answer: x = −0.2 ± 0.4i

The graph does not cross the x-axis. That is why we ended up with complex numbers.

In some ways it is easier: we don’t need more calculation, just leave it as −0.2 ± 0.4i.

### Example: Solve x2 − 4x + 6.25 = 0

Coefficients are:a=1, b=−4, c=6.25
Note that the Discriminant is negative:b2 − 4ac = (−4)2 − 4×1×6.25
= −9
Use the Quadratic Formula:x = −(−4) ± √(−9) 2

√(−9) = 3i
(where i is the imaginary number √−1)

So:x = 4 ± 3i 2

Answer: x = 2 ± 1.5i

The graph does not cross the x-axis. That is why we ended up with complex numbers.

BUT an upside-down mirror image of our equation does cross the x-axis at 2 ± 1.5 (note: missing the i).

Just an interesting fact for you!

## Summary

• Quadratic Equation in Standard Form: ax2 + bx + c = 0

factored

• Quadratic Formula: x = −b ± √(b2 − 4ac) 2a
• When the Discriminant (b2−4ac) is:
• positive, there are 2 real solutions
• zero, there is one real solution
• negative, there are 2 complex solutions

(Hard Questions:

1

2

3

4

5

6

7

8

)

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